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Oracle 11g - SQL pour calculer la différence de temps entre plusieurs lignes

Remarques.... vous ne devriez pas avoir de données redondantes (prénom, nom) dans cette table, vous devriez avoir une table séparée juste pour ça. Il semble que vos heures soient tronquées et non arrondies ? (l'arrondi donnerait 1,26 dans la première ligne).

with
     test_data ( seq, the_date, scanid, locatn, user_id, first_name, last_name ) as (
       select 103939758, to_date('05-NOV-16 14:36:22', 'dd-MON-yy hh24:mi:ss'), 194972, 'DOOR 19', 'AX9868', 'Mike', 'Derry'  from dual union all
       select 103939780, to_date('05-NOV-16 14:38:07', 'dd-MON-yy hh24:mi:ss'), 194972, 'DOOR 19', 'AX9868', 'Mike', 'Derry'  from dual union all
       select 103939792, to_date('05-NOV-16 14:39:24', 'dd-MON-yy hh24:mi:ss'), 194972, 'DOOR 19', 'AX9868', 'Mike', 'Derry'  from dual union all
       select 103940184, to_date('05-NOV-16 15:16:53', 'dd-MON-yy hh24:mi:ss'), 194972, 'DOOR 19', 'AX9868', 'Mike', 'Derry'  from dual union all
       select 103940185, to_date('05-NOV-16 15:51:41', 'dd-MON-yy hh24:mi:ss'), 194972, 'DOOR 19', 'AX9868', 'Mike', 'Derry'  from dual union all
       select 103940214, to_date('05-NOV-16 09:51:42', 'dd-MON-yy hh24:mi:ss'), 194993, 'DOOR 16', 'BC1910', 'Tony', 'McCann' from dual union all
       select 103940215, to_date('05-NOV-16 15:19:06', 'dd-MON-yy hh24:mi:ss'), 194993, 'DOOR 16', 'BC1910', 'Tony', 'McCann' from dual
     )
-- end of test data; solution (SQL query) begins below this line
select trunc(the_date) as the_date, user_id, first_name, last_name,
       trunc(24 * (max(the_date) - min(the_date)), 2) as total_hrs
from   test_data
group by trunc(the_date), user_id, first_name, last_name
;

THE_DATE  USER_ID FIRST_NAME LAST_NAME  TOTAL_HRS
--------- ------- ---------- --------- ----------
05-NOV-16 AX9868  Mike       Derry           1.25
05-NOV-16 BC1910  Tony       McCann          5.45