pour SQL Server 2005 et versions ultérieures, essayez :
;WITH SalesScore AS (
SELECT
s.PK_ID as S_PK
,c.PK_ID AS c_PK
,CASE
WHEN c.PK_ID IS NULL THEN 0
ELSE CASE WHEN s.ServiceId=c.ServiceId THEN 1 ELSE 0 END
+CASE WHEN (s.Address=c.Address AND s.Zip=c.Zip) THEN 1 ELSE 0 END
+CASE WHEN s.EmailAddress=c.EmailAddress THEN 1 ELSE 0 END
+CASE WHEN s.HomePhone=c.HomePhone THEN 1 ELSE 0 END
END AS Score
FROM Sales s
LEFT OUTER JOIN Customers c ON s.ServiceId=c.ServiceId
OR (s.Address=c.Address AND s.Zip=c.Zip)
OR s.EmailAddress=c.EmailAddress
OR s.HomePhone=c.HomePhone
)
SELECT
s.*,c.*
FROM (SELECT
S_PK,MAX(Score) AS Score
FROM SalesScore
GROUP BY S_PK
) dt
INNER JOIN Sales s ON dt.s_PK=s.PK_ID
INNER JOIN SalesScore ss ON dt.s_PK=s.PK_ID AND dt.Score=ss.Score
LEFT OUTER JOIN Customers c ON ss.c_PK=c.PK_ID
MODIFIER Je déteste écrire autant de code réel alors qu'il n'y avait pas de shema donné, car je ne peux pas réellement exécuter cela et être sûr que cela fonctionne. Cependant, pour répondre à la question de savoir comment gérer les liens en utilisant la dernière date de transaction, voici une version plus récente du code ci-dessus :
;WITH SalesScore AS (
SELECT
s.PK_ID as S_PK
,c.PK_ID AS c_PK
,CASE
WHEN c.PK_ID IS NULL THEN 0
ELSE CASE WHEN s.ServiceId=c.ServiceId THEN 1 ELSE 0 END
+CASE WHEN (s.Address=c.Address AND s.Zip=c.Zip) THEN 1 ELSE 0 END
+CASE WHEN s.EmailAddress=c.EmailAddress THEN 1 ELSE 0 END
+CASE WHEN s.HomePhone=c.HomePhone THEN 1 ELSE 0 END
END AS Score
FROM Sales s
LEFT OUTER JOIN Customers c ON s.ServiceId=c.ServiceId
OR (s.Address=c.Address AND s.Zip=c.Zip)
OR s.EmailAddress=c.EmailAddress
OR s.HomePhone=c.HomePhone
)
SELECT
*
FROM (SELECT
s.*,c.*,row_number() over(partition by s.PK_ID order by s.PK_ID ASC,c.LastTransaction DESC) AS RankValue
FROM (SELECT
S_PK,MAX(Score) AS Score
FROM SalesScore
GROUP BY S_PK
) dt
INNER JOIN Sales s ON dt.s_PK=s.PK_ID
INNER JOIN SalesScore ss ON dt.s_PK=s.PK_ID AND dt.Score=ss.Score
LEFT OUTER JOIN Customers c ON ss.c_PK=c.PK_ID
) dt2
WHERE dt2.RankValue=1