MySQL, Obtenir le classement des utilisateurs

SELECT  uo.*, 
        (
        SELECT  COUNT(*)
        FROM    users ui
        WHERE   (ui.points, ui.id) >= (uo.points, uo.id)
        ) AS rank
FROM    users uo
WHERE   id = @id

Rang dense :

SELECT  uo.*, 
        (
        SELECT  COUNT(DISTINCT ui.points)
        FROM    users ui
        WHERE   ui.points >= uo.points
        ) AS rank
FROM    users uo
WHERE   id = @id