Celui-ci le fera :
WITH d(y,v) AS (VALUES
(1,0),(2,0),(3,0),(4,33),(5,72),
(6,0),(7,0),(8,0),(9,0),(10,25),
(11,0),(12,56),(13,37)
)
SELECT grp, numrange(min(y),max(y),'[]') as ys, count(*) as len
FROM (
/* group identifiers via running total */
SELECT y, v, g, sum(g) OVER (ORDER BY y) grp
FROM (
/* group boundaries */
SELECT y, v, CASE WHEN
v IS DISTINCT FROM lag(v) OVER (ORDER BY y) THEN 1
END g
FROM d) s
WHERE v=0) s
GROUP BY grp
HAVING count(*) >= 3;